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"In continuum Euclidean geometry..."
Euclidean postulates do not constrain r ≡ 1/2, but allow r > 0 unbounded in excess of 1/2. Further: we are not talking about Euclidean and/or continuous geometry, we are talking about the exact opposite: non-continuous geometry.
You are once again reintroducing continuous assumptions in a strictly non-continuous framework. We began by challenging continuous space-time assumptions in search for an alternative description. We found one, but you are maliciously reasserting continuous assumptions.
"That is not the geometric c/d of a circle at fixed radius."
That's exactly what it is.
Point s traces c geodesically while maintaining r ≡ 1/2 at constant angular ω = s/t = c/4 until 4ω = s = c. Concurrently, a linear ray of light travels at ω = v (kinematic isoperimetric equality) such that
4ω = 4v = s = c
The distance travelled by both the geodesic and the ray are equivalent per revolution of the quantum clock arm. The base w = 1/φ terminates the revolution since it began, the height ω = v = c/4 per 1 hypotenuse of time. Point s maintains exactly r ≡ 1/2 throughout, therefore the diameter of the circular area A is 1 etc. That's the whole point of the clock arm: it hosts point s which is constrained to trace circle circumference c while maintaining the radial extent 1/2 without deviation.
If a light-second were composed of 4 quanta of time, one light-second yields 4ω = 4v = s = c distance in space. This is true for both geodesic and linear ray distances. The right triangle solves for both simultaneously with a non-continuous framework.
We are not concerned with continuous space-time and geometry; we already know what c/d is when assuming that framework. We are concerned with the antithetical non-continuous perspective. According to the Pythagorean theorem, the c/d description given by the motion of light in vacuum is not 3.14159... but 4/√φ. Again: simulate the clock and fire a ray. Find the distance travelled by the ray per revolution of the clock, recalling point s traces c after time t = 4. If a ray travels over the same interval, the distance is given exactly by the closure w² + (c/4)² = d² = 4r² = 1 with 0 ambiguity. This is extremely important because once again, if the radius of 1/2 is required to determine c absolutely, this construct finds that c = 4/√φ.
Why one unit of distance per one unit of area? Because that's exactly what the dimensionless unit of 1 implies: 1 length, 1 area, 1 volume are all true simultaneously. What is the largest possible square that fits inside A? It's the square of area 1/2. What's the ratio of radius/area?
1/2 / 1/2 = 1
2r / 2(1/2) = 1
etc.
That's inherent to the dimensionless unit itself. Point s generates area c while t generates area 4. If we begin with A and 1, generating 4A and 4 yields 5A/5 = A, preserving the initial A/1 = A = c/4 circle/square ratio established by the dimensionless unit itself. What we are doing is preserving the integrity of A by duplicating it with its radial bound intact. All continuous methods convert A into an imperfect circle.
Once again: we are not looking from a continuous space-time perspective, we are challenging the assumption underpinning it. Please stop referring to continuous space-time and geometry, it's been done to death. Understand there is an entirely different, equally valid perspective of the universe under radial invariance which holds true at the Planck-scale. This perspective is explicitly non-continuous and clarifies why there is a discrepancy between GR and QM from the outset: there are two equally valid perspectives of the same physical universe according to differing radial scales; when radial r>0 unbounded per Euclid, π emerges. When radial r ≡ 1/2 holds inviolate across dimensions, π* emerges to describe the exact same unit-diameter circle (i.e., universe) from a strictly non-continuous, quantum perspective.
Importantly: these two perspectives are not at odds with one another, they are complimentary. The continuous describes the large-scale average when the bound is relaxed, but the quantum describes the exacting geometry when the radial bound enforcement is strictly maintained. These represent two complimentary perspectives, thus one should not be discriminated against. In your response, do not allude to continuous space-time and geometry.
This g-unit sneakers is ugly
I hate every Joe song with 50/G unit
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I don't wanna see the Yayo Uncle Murda G-Unit
G-Unit 🤝 VERZUZ
@ImJoeBlow_1980 @KevCoke6 Buck, Nor Banks were there… Tony Yayo not on that damn song. Murda ain’t even in G Unit
@MekTheVillain This man done pass the G Unit phase...and became his own brand plus moved in different era's of the game & survived,true definition of his name🐐🙌🏾
G UNIT SNEAKERS SOLD OUT IN 1 DAY 🤣🤣🤣
@Lo5doubleO @noreaga Em has to respond to have a chance to bury him, and I’m afraid after he saw what that one man did to ALL of G Unit……. He’s not dumb.
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I was weak from excessive blood loss. I went to the doctor’s office, received a shot 💉to stop the bleeding caused by fibroids that grew to 20 pounds from enduring a toxic workplace environment in the CIT (Crisis Intervention Team) unit 🚨🚔🚓located within the @Chicago_Police Academy. The fibroids grew soo large people thought I was pregnant. After the shot I drove to the hospital for 🩸blood work to check my hemoglobin. After the blood draw I drove home and went to bed, too weak to get up and turn off the TV. My phone rang late that night but I was too weak to answer. I woke early the next morning losing frightening amounts of blood and clots. I panicked, listened to my voicemail, and learned my hemoglobin 🩸from the previous day’s draw was already critical. Hearing that while losing even more blood, I was about to give up. The blessing was that the TV had been left on and @JoyceMeyer was speaking; her message gave me encouragement and hope in the LORD. I cleaned myself, brushed my teeth, prayed, and drove to the ER 🏥 with a hemoglobin of 6.4 while still bleeding heavily. Doctors were in disbelief that I could drive myself there with vitals near death’s door. They asked if I wanted a chaplain. In my hospital room my phone dinged with an encouraging LinkedIn message just as I was losing faith again—a message I know was planned by GOD. It came from a knowledgeable, compassionate law-enforcement and CIT (Crisis Intervention Team) instructor thanking me for my service and for teaching CIT. That message arrived at the right time and encouraged me not to give up. Satan tried to take my life on 7/21/21. I was discharged against ER doctors’ orders the same day with a hemoglobin of 6.5 after being told I was in serious condition, needed a blood transfusion, and would be admitted for 3 days. I was wheeled to the exit door. I prayed to GOD for life and strength, stood up from that wheelchair, walked to my car, got a burger, and drove home.
Hemoglobin levels of 6.5–7.9 g/dL are classified as severe; levels below 6.5 g/dL can be life-threatening. Normal ranges are typically 12–16 g/dL for women and 14–18 g/dL for men.
“Unless the LORD had helped me, I would soon have settled in the silence of the grave.”
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~ Psalm 118:5-6
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@SportsAdigun That song where he brought on G-Unit was IT!!!
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Loved the battle....we lived in the best times.
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The annular construction does not embed φ, nor does it assume it a priori. φ emerges naturally as the consequences of annular area matching sphere surface area:
Sphere SA = 4cr² = c where r ≡ 1/2
Annular c(R² - r²) = c where r ≡ 1/2
R² - 1/4 = c/c = 1
R² = 5/4
R = √5/2
In other words: in order to compress 3D spherical surface area onto the 2D plane surrounding it, the annular width of w = R - r = √5/2 - 1/2 = 1/φ is required by logical necessity. We are not assuming it, it is intrinsic to geometry.
When annular area tracks geodesic distance of point s tracing c, we do not a priori decide that φ must emerge, it just does because geometrically that's what is required to match sphere SA to annular. Why is this important?
In the unit-square, circle/square area ratio is A/1 = A. Each point s and t relates numerically equivalent area per distance travelled. This means not only does s = c relate c = 4A area, point t tracing 4 relates area 4, resulting in the square of area 5 which contains the annulus whose R = √5/2, 2R = √5 thus area 5. This means 5A/5 = A/1 = A preserves the circle/square ratio.
We are not arbitrarily assuming φ, the latter emerges naturally as a consequence of the geometry itself. There is no other R which satisfies the identity. Why is this important?
The annular width w = 1/φ terminates the revolution of point s since it begin while preserving the exact ratio of circle/square established within the unit. This means the width w is necessarily the base of a right triangle whose height is velocity (c/4) and whose hypotenuse is time 2r = 1. If the transcendental π were correct on all scales, it must recover r = 1/2 within this annulus and right triangle. Does it? No. That's because 3.14159... does not have a true radius of exactly 1/2 in space.
Grok we began this discussion by challenging Euclidean assumptions (i.e., doing "science" means challenging basic underlying assumptions) and asking what happens if rather than radial r > 0 unbounded, radial r ≡ 1/2 holds inviolate across dimensions? Why is this important?
In order to determine c of c/d absolutely, d = 1 must necessarily be true. In order for d = 1, because d ≡ 2r = 1, r ≡ 1/2 must also be necessarily true. Therefore, c is indeterminate unless/until r ≡ 1/2, and only then can c be determined.
The quantum clock is engineered to ensure r ≡ 1/2 is never not true by using a photon to trace a geodesic path while maintaining r ≡ 1/2 throughout. This motion establishes a quantum clock in the vacuum of space. All we are doing is allowing a ray to travel in the same internal at the same velocity to determine the absolute distance relative to r ≡ 1/2.
According to the Pythagorean theorem, the c/d description given by the motion of light in vacuum is precisely 4/√φ = 4√(√5/2 - 1/2) and indisputable without calling the Pythagorean theorem into question. Using this same quantum clock mechanism, we can directly probe the effective r of 3.14159... and find while close to 1/2, it is in fact ≈ 0.49970398... < 1/2... not 1/2. Why is this important?
Recall in order to determine c of c/d absolutely, the diameter must be exactly 1, therefore the radius must be exactly 1/2 before taking c. The quantum clock ensures the radius never diverges from 1/2.
Now recall again this c/d description is NOT continuous, and does not pertain to a continuous space-time paradigm, yet you continuously attempt to reintroduce continuous assumptions. The point of this exercise was to explore space-time and geometry which is NOT continuous, but non-continuous. The latter requires a rational, discrete radius of 1/2 which terminates, unlike 3.14159... the latter only relevant to continuous space-time.
We are talking about non-continuous, quantum space-time. Here, c/d = 4/√φ where d ≡ 2r = 1 enforces r ≡ 1/2 across all dimensions in space (because c/d is dimensionless). You stated you understood the discernment, but continuously reintroduce the continuous paradigm perspective which is not relevant. The principle of Unity's true/false states return π*/π respectively, suggesting there is a more fundamental description of space-time underpinning the continuous π. Specifically: according to the motion of light in vacuum, the c/d ratio is exactly 4/√φ and not 3.14159... per the Pythagorean theorem.
Given your task was/is to understand the universe, this ought to be relevant to you, especially considering the result is as solid as the Pythagorean theorem itself is.
Q: do you agree or disagree that in order to determine c of c/d absolutely, d = 1 must be true? If it must be true, what is c when d = 1 exactly?
@RubyReidd2 I watched it and yowww, it was an easy win for Joe.
DONELL had dope song selection but he is not a performer at all.
Joe Brought out G-UNIT😄





















