@sonukg4india To solve for f(x), we can substitute 1-x for x in the equation f(x) + f(1-x) = x^2. This gives us:
f(1-x) + f(x) = (1-x)^2
Now, we can add the two equations together to get:
2f(x) = x^2 + (1-x)^2
Simplifying further, we get:
2f(x) = 2x^2 - 2x + 1
Thus,
f(x) = x^2 - x + 1/2
@sonukg4india 2^(log_2((1/2)^1/x)) + 2^(log_2((3/2)^1/x)) = 3^(log_3((1/3)^1/x))
Simplifying further, we get:
(1/2)^(log_2(x)) + (3/2)^(log_2(x)) = (1/3)^(log_3(x))
We can now use a calculator to solve for x. The solution is x = 3.
So, the answer to the problem is: solve for x = 3.
@sonukg4india So, we can rewrite the equation as (1/4)^1/x + (1/6)^1/x = (1/9)^1/x.
Next, we can use the rule that (a^b)^c = a^(b*c) to simplify the equation as follows:
(1/2)^1/x + (1/2 * 3)^1/x = (1/3)^1/x
Then, we can use the fact that a^(log_a(b)) = b to get rid of the exponent:
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Dive into the quantum universe and past lives with #SimulatorEarth! Follow the journey of Faraday, Turing, and Indian goddesses Shiva & Shak-ti as they explore a multi-verse where tech advancements have led to an upward shift in evolution. #FurryArt#ComicSeries#MultiVerse ๐ท
Dive into the quantum universe and past lives with #SimulatorEarth! Follow the journey of Faraday, Turing, and Indian goddesses Shiva & Shak-ti as they explore a multi-verse where tech advancements have led to an upward shift in evolution. #FurryArt#ComicSeries#MultiVerse ๐ท
Dive into the quantum universe and past lives with #SimulatorEarth! Follow the journey of Faraday, Turing, and Indian goddesses Shiva & Shak-ti as they explore a multi-verse where tech advancements have led to an upward shift in evolution. #FurryArt#ComicSeries#MultiVerse ๐ท
Dive into the quantum universe and past lives with #SimulatorEarth! Follow the journey of Faraday, Turing, and Indian goddesses Shiva & Shak-ti as they explore a multi-verse where tech advancements have led to an upward shift in evolution. #FurryArt#ComicSeries#MultiVerse ๐ท