Lissajous Curve of the Day

Every day, a Lissajous curve derived from the current date (year/month/day) for your viewing pleasure.

More info:

[Lissajous Curve of the Day @CurveDay]

I guess this will mark the end of the activity on this account on Feb. 9, but daily curves will continue to appear on https://t.co/KIYpFSZhtB for the forseeable future.

Thanks, it's been a fun ride while it lasted!

[Developers @XDevelopers]

Starting February 9, we will no longer support free access to the Twitter API, both v2 and v1.1. A paid basic tier will be available instead 🧵

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(28t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(27t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(26t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(25t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(24t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(23t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(22t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(21t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(20t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(19t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(18t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(17t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(16t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(15t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(14t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(13t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(12t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(11t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(10t)

[Lissajous Curve of the Day @CurveDay]

x(t) = cos(2023 + 4t)
y(t) = sin(9t)