@Oludeewon Let big radius be p1 & small radius be p2
Let q1 = big distance and q2= smaller distance
Distance btw the center is sum of their radii
d=r1+r2 = 8m+5m=13m
Using phythagoras,
13Β²=(p1-p2)Β²+5Β²
(P1-P2)Β²= 169-25
=12m
Distance from d left edge =8m
Distance btw centre P1 &P2 = 12m