MathsGenii

An e-learning website for learning mathematics for children aged 7 to 15 years. We provide complete curriculum coverage from Grade 1 to 10.

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What's the answer? Please tell us in the comments.⁠

Answer: D) 0

Explanation:

P(E) = favorable outcomes /total outcomes

Here favorable outcomes are '0'.

So probability is '0'.

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What's the answer? Please tell us in the comments.⁠

Answer: B) 2/3

Explanation:

S ={(1,5),(1,6),(1,7),(2,5),(2,6),(2,7),(3,5),(3,6),(3,7),(4,5),(4,6),(4,7)}

n(S) = 12

E ={(1,6),(2,5),(2,6),(2,7),(3,6),(4,5),(4,6),(4,7)}

n(E) = 8

P(E)=n(E)n(S)=8/12 = 2/3

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What's the answer? Please tell us in the comments.⁠

Answer: C) 0.7

Explanation:

P(atleast B) = P( B or A) = P(B) + P(A) = (0.3) + (0.4) = 0.7

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What's the answer? Please tell us in the comments.⁠

Answer: B) 103/108

Explanation:

Total number of events=6 x 6 x 6=216

So,B={(1,1,1),(1,1,2),(1,2,1),(2,1,1),(1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1)}

=10

P(B)=10/216

=> P(A) = 1 - P(B)

= 1 - (10/216) = 103/108

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What's the answer? Please tell us in the comments.⁠

Answer: B) p/(p+q)

Explanation:

Total number of cases=p+q

Favourable cases=p

Probability of that event is=p/(p+q)

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What's the answer? Please tell us in the comments.⁠

Answer: C) 1/3

Explanation:

Total number = 6

Getting a 'multiple of 3' = 2

So, probability = 2/6 =1/3
⁠
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What's the answer? Please tell us in the comments.⁠

Answer: A) 3/91

Explanation:

n(S) = (15 – 1)! = 14 !

= (13 - 1)! = 12!

= n(E) = 12! X 3!

= n(E) / n(S) = 12! X 3 ! / 14!

= 12!x3x2 / 14x13x12! = 6/14x13 = 3/91

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What's the answer? Please tell us in the comments.⁠
⁠
Answer : A) Two
⁠
Explanation:⁠

FA - IN - TS
AF - IN - ST
⁠
When the letters are arranged in the alphabetical order, two remains the same.
⁠
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What's the answer? Please tell us in the comments.⁠
⁠
Answer : C) 1⁠

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What's your answer? Please tell us in the comments.

Answer: C) 21/38

Explanation:

n(S) = 20c2 = 190

n(E)= 15c2 = 105

Therefore, P(E) = 105/190 = 21/38

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