P = k ⋅ G ∈ E(ℤₚ)

[P = k ⋅ G ∈ E(ℤₚ) @MauriOnX]

@Snchz77Mike @CosmeFulanito0k It don't matter if you win by an inch or a mile. Winning's winning, try again in 4 years

[P = k ⋅ G ∈ E(ℤₚ) @MauriOnX]

@WikiLeaksQ @jmilei para cuando la ley warren!

[P = k ⋅ G ∈ E(ℤₚ) @MauriOnX]

@RodolfoBits @BitcoinAR @CarlosMaslaton @labitconf Tremendo hit y gran programa con carlos!