@chase_math1 I got the same result for p(0) and p(1) but that formula for p(x) doesn't check out, b/c when you input 1 there you get 3.5. Think slope=2.5
@McNamaraMath19@mathstud101@chase_math1 Boom. That's what I got. Simplifies to f(x)=6. You put in x, and the machine ignores what you put in, and just outputs 6.
@russ_math Good question. The only info you have is that it hits the ground. That means position is 0.Set s(t)=0, solve for t, then plug this into v(t)
@russ_math answer will become 0, but the other will become 40x^4, which is what we want.So in short, you don't need to count a constant as a sep. func.
@russ_math Try using the product rule to take the deriv of 8x^5, treating 8 as one function and x^5 as a second function. You're right, one part of the