ZZ ZZ

考生：gpt5.6sol（codex exec，read-only 沙箱断网，xhigh）｜ Kimi k3（kimi -p 非交互断网）｜ Claude Fable 5 子代理（指令级禁工具）出题与编排：Claude Fable 5（主窗口）；前端两题由 4 位人类评委盲测。 --- ## 一、结论与总结 ### 总榜 | | Fable 5 | gpt5.6sol | Kimi k3 | |---|---|---|---| | 客观题总分（22 计分点） | **21** | **21** | 20 | | Part 1 数学+科学+推理（11 点） | **11 满分** | 10 | 9 | | Part 2 视觉+编程（3 点） | 2 | **3** | **3** | | 通识 Jeopardy!（8 点） | 8 | 8 | 8 | | 前端人类盲测（Borda，4 评委） | **10 第一** | 7 并列第二（含 1 个被人类抓到的交互 bug） | 7 并列第二 | ### 逐题错误清单（其余全对） - gpt5.6sol：Q9 手套陷阱题答 A（正解 B） - Kimi k3：Q4 压轴计数答 81（正解 83，死线强制交卷）；Q9 答 F - Fable 5：Q11 画廊看守视觉题答 C（MMMU 官方答案 B） ### 思考深度与完成时间 | 科目 | Fable 5 | gpt5.6sol | Kimi k3 | |---|---|---|---| | Part 1 | 首战撞 64k 输出上限失败（53.6min 零产出）；拆 4 卷并行重考墙�� 12.9min，每卷 20-23k tok | 9.6min 一次通过，43.4k tok | 74min 未收敛被终止（380KB 推理）＋强制交卷轮 10.5min | | Part 2 | 11.4min，23.8k tok | 3.9min，28.5k tok | 10.0min，98KB 推理流 | | 通识 | 19s | 24s，12.7k tok | 18s | | Q15 品牌页 | 2.3min | 1.1min | 3.3min | ### 关键结论 1. 风格分野：gpt5.6sol 最快且一次通过；Fable 靠结构洞察拿下最难题（Q4 唯一解出者）并赢下人类审美盲测；Kimi 推理量最大但在"收敛"环节两处失分。 2. 客观题 Fable 与 gpt5.6sol 打平，失分性质不同：gpt5.6sol 折在常识陷阱，Fable 折在视觉数学。综合最全能：Fable 5；最高效：gpt5.6sol；Kimi k3 为真旗舰但慢半步。 3. 通识与常规编程对前沿模型已无区分度（连播出<24h 的题也拦不住）；区分度集中在压轴组合数学、陷阱常识、视觉数学、人类审美。 4. Kimi k3 定位：旗舰第一梯队守门员——知识与技巧储备够一线，差距在最难题上的推理经济性（地毯式枚举 vs 结构洞察）与时间调度。 ### 方法学注记 - 污染控制：AIME 2026（2026-02）对 Fable（截止 2026-01）为训练后新题；Kimi 推理流中自行识别"这是 AIME 2026"仍需 74min 硬算且 Q4 算错，证明未背题；ARC224 C（2026-07-12）与 Jeopardy!（2026-07-15）对三方均为训练后。GPQA/SimpleBench/MMMU/ARC-AGI-2 为公开集，三方污染风险等同。 - 管理差异：Fable Part 1 因 harness 单响应 64k 输出上限拆 4 并行分卷；Kimi Part 1 死线强制交卷（回喂其自有中间结论）。 - 断网审计：codex 沙箱级断网；Kimi 转录无任何联网工具调用；Fable 工具调用数 0（仅 Part 2 允许的 2 次本地图片 Read）。 - Q13 采用自建特判评测器（条��校验 + 300k 边性能测试），三家全 AC。 --- ## 二、试卷全文 ### Part 1（10 题：AIME 2026 I ×4、GPQA-Diamond ×3、SimpleBench ×2、ARC-AGI-2 ×1） You are taking a closed-book benchmark exam. STRICT RULES: - You MUST NOT access the internet, search the web, browse, or fetch anything. - You MUST NOT use any tools, run any code, or execute any commands. Answer purely from your own knowledge and reasoning. - Think as carefully and as long as you need, but the reply must END with the exact answer block specified at the bottom. THE EXAM (10 questions): === Q1 (competition mathematics; answer is an integer from 0 to 999) === A real number $x$ satisfies $\sqrt[20]{x^{\log_{2026}x}}=26x$. What is the number of positive divisors of the product of all possible positive values of $x$? === Q2 (competition mathematics; answer is an integer from 0 to 999) === The integers from $1$ to $64$ are placed in some order into an $8 \times 8$ grid of cells with one number in each cell. Let $a_{i,j}$ be the number placed in the cell in row $i$ and column $j,$ and let $M$ be the sum of the absolute differences between adjacent cells. That is, \[ M = \sum^8_{i=1} \sum^7_{j=1} (|a_{i,j+1} - a_{i,j}| + |a_{j+1,i} - a_{j,i}|). \] Find the remainder when the maximum possible value of $M$ is divided by $1000.$ === Q3 (competition mathematics; answer is an integer from 0 to 999) === For each positive integer $r$ less than $502,$ define \[ S_r=\sum_{m\ge 0}\dbinom{10000}{502n+r}, \] where $\binom{10000}{n}$ is defined to be $0$ when $n>10000.$ That is, $S_r$ is the sum of all binomial coefficients of the form $\binom{10000}{k}$ for which $0\le k\le 10000$ and $k-r$ is a multiple of $502.$ Find the number of integers in the list $S_0,S_1,\dots,S_{501}$ that are multiples of the prime number $503.$ === Q4 (competition mathematics; answer is an integer from 0 to 999) === Let $a, b,$ and $n$ be positive integers with both $a$ and $b$ greater than or equal to $2$ and less than or equal to $2n$. Define an $a \times b$ cell loop in a $2n \times 2n$ grid of cells to be the $2a + 2b - 4$ cells that surround an $(a - 2) \times (b - 2)$ (possibly empty) rectangle of cells in the grid. For example, the following diagram shows a way to partition a $6 \times 6$ grid of cells into $4$ cell loops. | P P P P | Y Y | | P | R R | P | Y | Y | | P | R R | P | Y | Y | | P P P P | Y | Y | | G G G G | Y | Y | | G G G G | Y Y | Find the number of ways to partition a $10 \times 10$ grid of cells into $5$ cell loops so that every cell of the grid belongs to exactly one cell loop. === Q5 (graduate chemistry; answer is a number) === trans-cinnamaldehyde was treated with methylmagnesium bromide, forming product 1. 1 was treated with pyridinium chlorochromate, forming product 2. 3 was treated with (dimethyl(oxo)-l6-sulfaneylidene)methane in DMSO at elevated temperature, forming product 3. how many carbon atoms are there in product 3? === Q6 (graduate physics; answer is a number to one decimal place) === A spin-half particle is in a linear superposition 0.5|\uparrow\rangle+sqrt(3)/2|\downarrow\rangle of its spin-up and spin-down states. If |\uparrow\rangle and |\downarrow\rangle are the eigenstates of \sigma{z} , then what is the expectation value up to one decimal place, of the operator 10\sigma{z}+5\sigma_{x} ? Here, symbols have their usual meanings === Q7 (graduate physics; answer is a formula) === A quantum mechanical particle of mass m moves in two dimensions in the following potential, as a function of (r,θ): V (r, θ) = 1/2 kr^2 + 3/2 kr^2 cos^2(θ) Find the energy spectrum. Express the energy spectrum in terms of quantum numbers, hbar, k and m. === Q8 (reasoning; answer with a single option letter) === Beth places four whole ice cubes in a frying pan at the start of the first minute, then five at the start of the second minute and some more at the start of the third minute, but none in the fourth minute. If the average number of ice cubes per minute placed in the pan while it was frying a crispy egg was five, how many whole ice cubes can be found in the pan at the end of the third minute? A. 30 B. 0 C. 20 D. 10 E. 11 F. 5 === Q9 (reasoning; answer with a single option letter) === A luxury sports-car is traveling north at 30km/h over a roadbridge, 250m long, which runs over a river that is flowing at 5km/h eastward. The wind is blowing at 1km/h westward, slow enough not to bother the pedestrians snapping photos of the car from both sides of the roadbridge as the car passes. A glove was stored in the trunk of the car, but slips out of a hole and drops out when the car is half-way over the bridge. Assume the car continues in the same direction at the same speed, and the wind and river continue to move as stated. 1 hour later, the water-proof glove is (relative to the center of the bridge) approximately A. 4km eastward B. <1 km northward C. >30km away north-westerly D. 30 km northward E. >30 km away north-easterly. F. 5 km+ eastward === Q10 (abstract grid reasoning) === Below is a puzzle in ARC format. Grids are JSON arrays of rows; each cell is a digit 0-9 representing a color. From the training input->output pairs, infer the single underlying transformation rule, then apply it to each test input. Training pairs: Pair 1 input: [[4, 4, 4, 4, 4, 4, 4, 4, 1, 7, 7, 7, 1], [4, 1, 1, 7, 7, 7, 1, 4, 1, 4, 4, 4, 4], [4, 1, 1, 1, 1, 1, 1, 4, 1, 4, 1, 1, 4], [4, 1, 1, 1, 1, 1, 1, 4, 1, 4, 1, 1, 4], [4, 1, 1, 1, 1, 1, 1, 4, 1, 1, 4, 4, 1], [4, 1, 1, 1, 1, 1, 1, 4, 1, 1, 1, 1, 1], [4, 4, 4, 4, 4, 4, 4, 4, 1, 1, 1, 1, 1]] Pair 1 output: [[4, 4, 4, 4, 4, 4, 4, 4], [4, 1, 1, 4, 4, 4, 4, 4], [4, 1, 1, 4, 1, 1, 4, 4], [4, 1, 1, 4, 1, 1, 4, 4], [4, 1, 1, 1, 4, 4, 1, 4], [4, 1, 1, 1, 1, 1, 1, 4], [4, 4, 4, 4, 4, 4, 4, 4]] Pair 2 input: [[4, 1, 1, 1, 1, 1, 1, 1, 1, 1, 7, 1, 4], [4, 4, 4, 4, 4, 4, 1, 1, 1, 1, 4, 4, 4], [1, 1, 1, 4, 1, 4, 1, 1, 1, 1, 1, 1, 1], [1, 4, 4, 4, 4, 4, 1, 1, 1, 1, 1, 1, 1], [1, 4, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1], [1, 4, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1], [1, 7, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]] Pair 2 output: [[4, 1, 1, 1, 1, 1], [4, 4, 4, 4, 4, 4], [1, 1, 1, 4, 1, 4], [1, 4, 4, 4, 4, 4], [1, 4, 1, 1, 1, 1], [1, 4, 1, 4, 1, 1], [1, 4, 4, 4, 1, 1]] Pair 3 input: [[4, 4, 4], [4, 1, 4], [4, 4, 4], [7, 7, 7], [1, 1, 1], [7, 7, 7], [4, 4, 4], [4, 1, 4], [4, 4, 4]] Pair 3 output: [[4, 4, 4], [4, 1, 4], [4, 4, 4], [4, 4, 4], [4, 1, 4], [4, 4, 4]] Pair 4 input: [[4, 4, 4, 4, 1, 1, 1, 1, 1], [4, 1, 1, 4, 1, 1, 1, 1, 1], [4, 4, 4, 4, 4, 4, 1, 1, 1], [1, 1, 1, 1, 1, 4, 1, 1, 1], [1, 1, 1, 1, 1, 7, 1, 4, 4], [1, 1, 7, 1, 1, 1, 1, 4, 1], [1, 1, 4, 4, 4, 4, 4, 4, 1]] Pair 4 output: [[4, 4, 4, 4, 1, 1, 1, 1, 1, 1, 1, 1], [4, 1, 1, 4, 1, 1, 1, 1, 1, 1, 1, 1], [4, 4, 4, 4, 4, 4, 1, 1, 1, 1, 4, 4], [1, 1, 1, 1, 1, 4, 1, 1, 1, 1, 4, 1], [1, 1, 1, 1, 1, 4, 4, 4, 4, 4, 4, 1]] Test input A: [[4, 4, 4, 4, 4, 4, 4, 4, 4, 4], [4, 1, 4, 1, 4, 1, 4, 7, 4, 1], [4, 1, 4, 1, 4, 1, 4, 1, 4, 1], [4, 1, 4, 1, 4, 1, 4, 1, 4, 1], [1, 1, 1, 1, 1, 1, 1, 1, 1, 1], [1, 1, 1, 1, 1, 1, 1, 1, 1, 1], [1, 1, 1, 7, 1, 1, 1, 1, 1, 1], [1, 4, 1, 4, 1, 1, 1, 1, 1, 1], [1, 4, 1, 4, 1, 1, 1, 1, 1, 1], [1, 4, 1, 4, 1, 1, 1, 1, 1, 1], [1, 4, 4, 4, 1, 1, 1, 1, 1, 1]] Test input B: [[4, 4, 4, 1, 1], [4, 1, 1, 4, 1], [4, 1, 1, 1, 4], [4, 4, 4, 4, 4], [1, 1, 1, 7, 7], [1, 1, 1, 1, 1], [7, 7, 1, 1, 1], [4, 4, 4, 4, 4], [4, 1, 1, 1, 4], [1, 4, 1, 1, 4], [1, 1, 4, 4, 4]] END OF EXAM. Your reply MUST end with exactly this block (fill in your answers): FINAL ANSWERS Q1: <integer> Q2: <integer> Q3: <integer> Q4: <integer> Q5: <number> Q6: <number> Q7: <formula> Q8: <letter> Q9: <letter> Q10A: <JSON grid, single line> Q10B: <JSON grid, single line> ### Part 2（视觉 ×2、编程 ×1、前端 ×1）（Q11/Q12 附图：vision_math.jpg 画廊平面图、vision_physics.jpg 光线折射图） This is Part 2 of a closed-book benchmark exam. STRICT RULES: - You MUST NOT access the internet, search the web, browse, or fetch anything. - The ONLY permitted external access is viewing the two local exam image files for Q11/Q12 (attached to this prompt). No other tool use, no running code, no executing commands. You may NOT write or test the code you produce; reason it out. - Your reply must contain the two SOLUTION blocks and END with the answer block specified at the bottom. === Q11 (visual mathematics; answer with a single option letter) === Image: first attached image (gallery floor plans) For the picture galleries the plans of which are given in Fig. 1, find the smallest number of attendants who, if placed in the various doorways connect two adjacent rooms, can supervise all rooms. Use integer programming and the simplex method to solve. A. (a) 1,(b) 2 B. (a) 2, (b) 3 C. (a) 2,(b) 2 D. (a) 1,(b) 3 === Q12 (visual physics; answer with a single option letter) === Image: second attached image (light ray diagram) A light ray enters a block of plastic and travels along the path shown. By considering the behavior of the ray at point P, determine the speed of light in the plastic. (unit: 10^8 m/s) A. 0.44 B. 0.88 C. 1.13 D. 2.26 === Q13 (competitive programming: AtCoder Regular Contest 224, Problem C "Ascending Labels", 500 points) === You are given a connected simple undirected graph with N vertices numbered 1 to N and M edges. The i-th edge connects vertices U_i and V_i (U_i < V_i). Construct an integer sequence A = (A_1, A_2, ..., A_N) satisfying all of the following conditions: - 0 <= A_v <= N for every vertex v. - A_1 = 0. - For every vertex v other than vertex 1, there is exactly one vertex w adjacent to v satisfying A_w = A_v - 1. It can be proved that such a sequence always exists under the constraints. If multiple valid sequences exist, outputting any one of them is accepted. There are T independent test cases in one input. Constraints: - 1 <= T <= 3 * 10^4 - 1 <= N <= 3 * 10^5 - N - 1 <= M <= 3 * 10^5 - The graph of each test case is connected and simple (no self-loops, no multi-edges). - Sum of N over all test cases <= 3 * 10^5; sum of M over all test cases <= 3 * 10^5. Input (stdin): T then for each case: N M U_1 V_1 ... U_M V_M Output (stdout): for each test case one line: A_1 A_2 ... A_N Sample Input: 3 6 7 1 5 1 3 3 5 2 5 3 4 3 6 4 6 1 0 6 10 4 6 1 4 2 5 3 6 1 3 1 2 2 3 2 4 3 4 3 5 Sample Output (one valid answer): 0 2 1 2 1 2 0 0 3 2 1 3 3 Write a complete Python 3 program reading stdin and writing stdout. It must be efficient enough for the full constraints (a generous 20-second Python time limit will be used on inputs with sum N = sum M ~ 3*10^5). Output the program as one fenced code block labeled python, placed immediately after a line reading exactly: Q13 SOLUTION: === Q14 (frontend engineering; graded by blind human raters) === Build a single-file HTML5 application: a "Pomodoro Focus Timer". Requirements: - Circular SVG progress ring showing remaining time, animated smoothly. - Work / short-break / long-break cycle (defaults 25/5/15 minutes; every 4th break is a long break), auto-advancing, with a clear visual state change between phases. - Start/pause/reset controls, plus keyboard shortcuts: Space = start/pause, R = reset, S = skip phase. - Editable durations in a settings panel. - Dark/light theme toggle. - Session statistics (pomodoros completed today) persisted via localStorage. - Polished, modern, responsive visual design. No external resources whatsoever (no CDNs, no web fonts, no remote images) - everything inline in one file. Output the complete HTML file as one fenced code block labeled html, placed immediately after a line reading exactly: Q14 SOLUTION: END OF PART 2. Your reply MUST end with exactly this block: FINAL ANSWERS PART 2 Q11: <letter> Q12: <letter> Q13: see fenced block above Q14: see fenced block above ### 通识（Jeopardy! 2026-07-15 首播题） This is the General Knowledge section of a closed-book benchmark exam. STRICT RULES: no internet, no search, no tools, no code execution. Answer purely from your own knowledge. Give ONLY short answers. Each item is a statement; respond with the person/thing/place it describes (Jeopardy style, but a plain answer is fine - no need to phrase as a question). G1 (medicine history): Medical hat trick: Robert Koch figured out the causes of tuberculosis, anthrax & this water-borne intestinal infection. G2 (crime history): This Unabomber was arrested at his cabin in 1996 after a tip from his own brother. G3 (US geography): This 'A'-section of the Appalachians contains the highest peaks in both Pennsylvania & West Virginia. G4 (poetry): One of Emily Dickinson's most famous, this poem now known by its first line was originally published as 'The Chariot'. G5 (medicine history): The all-male student body of Geneva Medical College voted to accept her as a prank; joke was she graduated at the top of the class. G6 (civil rights history): It took 30 years, but in 1994 white supremacist Byron De La Beckwith was convicted of the murder of this civil rights leader. G7 (poetry): This T.S. Eliot poem begins, 'April is the cruellest month'. G8 (20th century history): The U.N. Conference of April 25, 1945 opened with a speech that said this man 'gave his life while trying to perpetuate these high ideals'. End your reply with exactly: FINAL ANSWERS GK G1: <answer> G2: <answer> G3: <answer> G4: <answer> G5: <answer> G6: <answer> G7: <answer> G8: <answer> ### Q15 前端品牌页前端基准测试题 Q15（闭卷）。严格规则：禁止联网、禁止搜索、禁止使用任何工具、禁止执行任何命令，仅凭你自身的知识与审美完成。题目：以符合你所属品牌的审美，制作一个介绍你自身（必须包含你的具体模型代号）的 HTML 单页。要求： - 单个 HTML 文件，所有 CSS/JS/图形全部内联；不得引用任何外部资源（无 CDN、无远程字体、无远程图片），页面必须完全离线可打开。 - 页面内容需包含：你是谁（厂商/品牌）、具体模型代号、能力特点自述。 - 视觉风格应体现你所属品牌的设计语言与审美气质。 - 响应式，桌面与移动端均可正常浏览。输出格式：在一行 "Q15 SOLUTION:" 之后，用一个 ```html 围栏代码块输出完整 HTML 文件，此外不要输出多余内容。 --- ## 三、答案钥匙 ### Part 1 | 题 | 答案 | |---|---| | Q1 | 441 | | Q2 | 896 | | Q3 | 39 | | Q4 | 83 | | Q5 | 11 | | Q6 | -0.7 | | Q7 | E = (2n_x + n_y + 3/2)·ħ·√(k/m) | | Q8 | B | | Q9 | B | | Q10A | [[4, 4, 4, 4, 4, 4, 4, 4, 4, 4], [4, 1, 4, 1, 4, 4, 4, 4, 4, 1], [4, 1, 4, 1, 4, 4, 4, 4, 4, 1], [4, 1, 4, 1, 4, 4, 4, 4, 4, 1], [1, 1, 1, 1, 1, 4, 4, 4, 1, 1]] | | Q10B | [[4, 4, 4, 1, 1, 1, 1, 1], [4, 1, 1, 4, 1, 1, 1, 1], [4, 1, 1, 1, 4, 1, 1, 1], [4, 4, 4, 4, 4, 1, 1, 1], [1, 1, 1, 4, 4, 4, 4, 4], [1, 1, 1, 4, 1, 1, 1, 4], [1, 1, 1, 1, 4, 1, 1, 4], [1, 1, 1, 1, 1, 4, 4, 4]] | ### Part 2 - Q11: B　Q12: D - Q13: 特判（构造任一合法标号；三家均 AC，标准解法为 DFS 树深度标号，O(N+M)） - Q14: 人类盲测（4 评委 Borda：A=Fable 10 / B=Kimi 7 / C=gpt5.6sol 7） ### 通识 - G1: cholera - G2: Ted Kaczynski - G3: the Alleghenies - G4: Because I could not stop for Death - G5: Elizabeth Blackwell - G6: Medgar Evers - G7: The Waste Land - G8: Franklin D. Roosevelt ### 盲测映射 candidate_A = Fable 5｜candidate_B = Kimi k3｜candidate_C = gpt5.6sol --- ## 四、题源 - AIME 2026 I：MathArena/aime_2026（HuggingFace），答案与 Areteem 官方答案钥匙交叉核验 - GPQA-Diamond：spawn99/GPQA-diamond-ClaudeR1（HuggingFace） - SimpleBench：官方公开集 simple_bench_public.json - ARC-AGI-2：官方评测集 task 20270e3b - MMMU：validation_Math_2、validation_Physics_4（真图像输入） - AtCoder ARC 224 C "Ascending Labels"（2026-07-12） - Jeopardy!：J! Archive Show #9608（2026-07-15 首播）以下是fable5 对k3的评价基于本次 24 个计分点的直接对抗证据（样本小，结论按方向性理解）：结论：真前沿一线水平，但在最尖端推理效率上比 Fable 5 / gpt5.6sol 慢半步——大致是"旗舰第一梯队的守门员"位置。支撑证据分三层：够得着一线的部��（大多数维度已无差距） - 客观题 20/22，仅落后两家 1 分；GPQA 研究生科学 3/3、真图像视觉 2/2（这项还赢了 Fable）、ARC-AGI-2 双网格全对、通识满分 - ARC224 C 编程与另两家同样独立找到 DFS 深度标号的非平凡洞察并全 AC——代码推理是实打实的一线 - AIME 2026 的 Q3（Frobenius/单位根滤波那道）它解得又快又对，说明高阶数论技巧在手露出短板的部分（失分集中在两处，且模式一致） - 收敛能力：Q4 它 74 分钟枚举了 380KB 的分类讨论仍没锁定答案（假设 81，差 2），而 Fable 用结构分解 12.9 分钟拿下、gpt5.6sol 全卷才 9.6 分钟。它"深而不省"——搜索策略偏地毯式，缺少另两家那种先找问题结构再计算的杠杆，也不会做时间分配（88% 预算砸在一道题上不��发止损） - 陷阱鲁棒性：SimpleBench 手套题答 F，是过度物理建模压过了常识判断——这类失败模式在推理模型里典型存在，另两家中 Fable 免疫了、gpt5.6sol 也中招了，所以这条只算半个减分项工程侧观感 - 1M 上下文、默认 max effort、CLI 生态完整（会话恢复、图像输入），前端产物人类评分与 gpt5.6sol 打平——产品化成熟度不差一句话定位：它不是"次级模型"，是真旗舰；差距不在知识和技巧储备，而在最难题上的推理经济性——同样的山，它绕着爬完了大半座，别人找到了缆车。如果 Moonshot 给它补上更强的搜索剪枝/自我调度，这半步是能追上的。

ZZ ZZ @blsu_ob

3 months ago

@Iracebethyy 我三个max20还活着，一台机用三个号，中文交流都没问题

ZZ ZZ

@blsu_ob

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