DailyMathVisuals

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[DailyMathVisuals @dailymathvisual]

You're rushing to your gate. Two paths to the same place.
• Short path: 80 m on normal floor at 1 m/s → 80 seconds
• Walkway path: 120 m at 2 m/s → 60 seconds
The LONGER path wins by 20 seconds.
The math is one line:
time = distance / speed
Distance is only half the story. Speed is the other half.
A longer path at a faster speed can beat a shorter path at a slower one.
The shortest path is not always the fastest path.
Next time you're racing to a gate — take the walkway.
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#math #physics #speed #distance #airport #stem #mathvisuals #studygram #mathshorts

[DailyMathVisuals @dailymathvisual]

1, 2, 4, 8, 16, ___
What comes next?
The doubling pattern says 32.
Reality says 31.
Here's the setup. Place n points on a circle. Draw every chord between them. Count the regions.
n=1 → 1
n=2 → 2
n=3 → 4
n=4 → 8
n=5 → 16
n=6 → 31 ← not 32
The powers-of-2 pattern was a coincidence. Holds for five cases. Breaks at the sixth.
The real formula is
R(n) = 1 + C(n,2) + C(n,4)
• 1 = the initial disk
• C(n,2) = the chords
• C(n,4) = the interior crossings (every 4 points gives exactly one crossing)
Plug in n=6: 1 + 15 + 15 = 31. ✓
The lesson: a pattern that holds for 5 cases is not a proof.
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#math #combinatorics #patterns #moser #stem #mathvisuals #studygram #mathshorts #counterintuitive

[DailyMathVisuals @dailymathvisual]

Why is ∫eˣ dx = eˣ + C?
Because eˣ is the only exponential that is its own derivative.
Here's how you can see it.
Every curve y = aˣ passes through (0, 1).
At that point the height is 1.
Look at the tangent slope at that point:
• y = 2ˣ → slope = ln(2) ≈ 0.69 → too shallow
• y = 3ˣ → slope = ln(3) ≈ 1.10 → too steep
Somewhere between 2 and 3 there's a base where the slope at (0,1) equals exactly 1.
That base is e ≈ 2.71828.
And it's not just at (0,1). For y = eˣ, the slope equals the height at every single point on the curve.
d/dx [eˣ] = eˣ
Reverse the arrow:
∫ eˣ dx = eˣ + C
That's the whole reason e exists. It's the goldilocks base where the function and its slope match.
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#math #calculus #exponential #eulersnumber #integral #derivative #stem #mathvisuals #studygram #mathshorts

[DailyMathVisuals @dailymathvisual]

The cleanest trick in calculus.
∫ sec(x) dx = ?
Multiply by (sec(x) + tan(x))/(sec(x) + tan(x)). The numerator becomes EXACTLY the derivative of the denominator.
Let u = sec(x) + tan(x) → ∫ du/u = ln|u| + C.
∫ sec(x) dx = ln|sec(x) + tan(x)| + C ✓
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[DailyMathVisuals @dailymathvisual]

Can 3 cuts make 8 pieces?
Flat pizza: max 7.
Thick cake: 8.
2D: 1 + 1 + 2 + 3 = 7. (max with n cuts = 1 + n(n+1)/2)
3D: 1 + 1 + 2 + 4 = 8.
In 2D each cut is a line. In 3D each cut is a plane. Dimension does the rest.
Follow @dailymathvisuals for daily visual math.
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[DailyMathVisuals @dailymathvisual]

Every 2026 World Cup squad has at least 3 players born in the same month. Always.
• 26 players (FIFA squad size)
• 12 months
• ⌈26 / 12⌉ = 3
The Pigeonhole Principle.
More: Any 13 footballers → 2 share a month. 380 PL matches in 30 scoreline buckets → some bucket has 13+ matches.
Follow @dailymathvisuals for daily visual math.
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[DailyMathVisuals @dailymathvisual]

Math contest Q39 — A cubical sponge absorbs water at 2 in³/min. How fast is the edge growing when V = 8 in³?
V = s³
dV/dt = 3s²·(ds/dt)
At V = 8 → s = 2
2 = 12·(ds/dt) → ds/dt = 1/6 in/min ✓
Answer: (b)
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[DailyMathVisuals @dailymathvisual]

@Meta @MetaforBusiness @facebook @instagram @boztank @andymstone @mosseri @NOBFixx Would be able to help on this one please?

[Servet Bayuk @servet_bayuk]

@dailymathvisual @Meta @MetaforBusiness @facebook @instagram @boztank @andymstone @mosseri One of the best tech advisors I’ve worked with. Quick and effective solutions.

[DailyMathVisuals @dailymathvisual]

@Tokfno @Nobfixx Meta support team hasn't responded to the support emails raised. Not even an acknowledgment for the case.

[Joanne P.! 🇺🇸🇺🇸Follow MAGA #MAGA @Tokfno]

Have you sent an email to the support team??
I was referred to this cyber security expert by a colleague who was a former Meta employee, and twitter X he’s the best partner's with Meta any kind of recovery,you should contact him for help @NOBFixx on Twitter support

[DailyMathVisuals @dailymathvisual]

@Tokfno @Nobfixx Thank you @justjp5 I have reached out to @Nobfixx

[Joanne P.! 🇺🇸🇺🇸Follow MAGA #MAGA @Tokfno]

I think their support system is out of service because I also tried all platforms to contact them to resolve same issue and it was of no use, I will advise you check @nobfixx ON X am sure he can fix the issue because he also fixed mine

[DailyMathVisuals @dailymathvisual]

@Meta @MetaforBusiness @facebook @instagram @boztank @andymstone @mosseri @NOBFixx Would be able to help on this one please?

[DailyMathVisuals @dailymathvisual]

@Meta @MetaforBusiness @facebook @instagram @boztank @andymstone @mosseri

My Business Manager has been hijacked. The unauthorized admin has Full Control of my account, and the email shown for them has CHANGED since the compromise, confirming active tampering. The current email is [email protected], which is not a real Meta support address — it's a deliberate impersonation of "FB Support."

I'm the legitimate owner of @dailymathvisuals. Business Manager ID: 1332629101972277. Date of compromise: June 10, 2026.

I've submitted 4+ reports through official Meta channels and received zero response. Please help — this needs to go to your Trust & Safety / impersonation team, not standard account recovery.

[DailyMathVisuals @dailymathvisual]

@Meta @MetaforBusiness

My Business Manager has been hijacked. On June 10, 2026, an unauthorized user gained Full Control admin access to my Business Manager without my consent. I am the legitimate owner of @dailymathvisuals, a small
educational math channel.

The unauthorized admin currently shows as [email protected] — which is a Gmail address deliberately impersonating Meta support, and the email has been changed since the initial compromise, confirming
active tampering.

My Business Manager ID is 1332629101972277 and my account email is [email protected]. I have submitted four reports through official Meta support channels and received zero response.

I have signed up for Meta Verified for Business with no chat support made available. I have attempted in-app removal of the unauthorized admin, blocked because they hold the higher role. Please escalate this to your Business Integrity / Trust & Safety team —
specifically the impersonation queue, not standard account recovery.

I am willing to verify my identity through any method Meta requires. Screenshot of the unauthorized admin in the People list attached.

[DailyMathVisuals @dailymathvisual]

RT @dailymathvisual: @Meta @MetaforBusiness

my Business Manager has been hijacked. On June 10, 2026, an unauthorized user gained Full Co…

[DailyMathVisuals @dailymathvisual]

@Meta @MetaforBusiness @facebook @instagram @boztank @andymstone @mosseri

My Business Manager has been hijacked. The unauthorized admin has Full Control of my account, and the email shown for them has CHANGED since the compromise, confirming active tampering. The current email is [email protected], which is not a real Meta support address — it's a deliberate impersonation of "FB Support."

I'm the legitimate owner of @dailymathvisuals. Business Manager ID: 1332629101972277. Date of compromise: June 10, 2026.

I've submitted 4+ reports through official Meta channels and received zero response. Please help — this needs to go to your Trust & Safety / impersonation team, not standard account recovery.

[DailyMathVisuals @dailymathvisual]

@Meta @MetaforBusiness

My Business Manager has been hijacked. On June 10, 2026, an unauthorized user gained Full Control admin access to my Business Manager without my consent. I am the legitimate owner of @dailymathvisuals, a small
educational math channel.

The unauthorized admin currently shows as [email protected] — which is a Gmail address deliberately impersonating Meta support, and the email has been changed since the initial compromise, confirming active tampering.

My Business Manager ID is 1332629101972277 and my account email is [email protected]. I have submitted four reports through official Meta support channels and received zero response.

I have signed up for Meta Verified for Business with no chat support made available. I have attempted in-app removal of the unauthorized admin, blocked because they hold the higher role. Please escalate this to your Business Integrity / Trust & Safety team - specifically the impersonation queue, not standard account recovery.

I am willing to verify my identity through any method Meta requires. Screenshot of the unauthorized admin in the People list attached.