@HotOompaLoompa@RoKhannaNews But OP’s point is well taken, that as literal US representatives, they probably should have just said “USA” and called it a day, if only to stop making attack ad clip farming so easy for the republicans.
@HotOompaLoompa@RoKhannaNews Yeah, this clip is mostly just a reflection of how little Americans care about soccer. The World Cup has no real stakes here, so *most* people just pick a random country to root for and it’s not considered a big deal.
If it was the Olympics they would have answered differently.
There’s a lot of artists that dropped great music in 2020-21 and never really got to capitalize off of it because of the pandemic. I always feel a little bad for them when revisiting those albums.
@JonathanJamz1@BoringMilner Then maybe invite fewer teams.
A lot of countries can’t put together enough competent athletes for the Winter Olympics sports either and no one’s shredding a tear for them…
This new Navy Blue x Earl song affirms what I’ve been thinking for a while, that a lot of these underground need to be rapping on faster beats.
Your delivery and beats can’t both be sleepy, at least not for 30+ minutes straight.
@TheBarcaCornerx@BoringMilner If it’s about player health, I’d just add in more substitutions. This quarter system is definitely to allow for a commercial break.
@RadishHarmers Ok I think I get it now. It took me working through the reverse case (if a cube were inscribed inside a unit sphere), in which case the cube volume is counterintuitively greater for all n>4.
My mistake. Thx for the discussion, sorry it took so long for the arguments to sink in.
@RadishHarmers And you’re correct that I originally used Va/Vb≈0.5 because of the problem definition, since the radius (d/2) by definition is half the side length (d). It’s true that the logic doesn’t hold for if r and d aren’t tied together.
@RadishHarmers That’s fair. A probably better way I could’ve approached it initially: The ratio R of any (convex?) object of volume Va inscribed in another (convex) object with Vb>Va will necessarily scale at (Va/Vb)^n, and therefore approach 0 as n->inf, since Va/Vb<1.
@RadishHarmers The fact that “a” also shrinks very quickly is true, but harder to intuit from basic assumptions which is why I like the 0.5^n explanation.
In fact your original probability argument also has the 0.5^n embedded in it (in the value of k), but just a level of abstraction away.
@RadishHarmers As long as a doesn’t grow exponentially, the volume ratio of the inscribed sphere to the cube will approach 0 as n->infinity (because (1/2)^n will approach 0 exponentially fast). Which is all we’re trying to show for an intuitive explanation for the original question.
@RadishHarmers My logic, which feels simpler: Cube volumes scale at d^n, (d=side length; n=dimension). The inscribed sphere scales at a*(d/2)^n, where a is a scalar and to first order, a≈1.
So the ratio of sphere:cube volumes will be ~ (1/2)^n, decreasing exponentially.