Top Tweets for #wayToBigTech
978. Longest Turbulent Subarray
- Nice idea to save the previous state and not check the future state
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53. Maximum Subarray
- A sliding window is helpful in problems like this (my solution)
- But, the divide and conquer technique could make your search much more faster :)
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4. Median of Two Sorted Arrays
What a great solution (not mine) for this task with binary search! It's crazy! Do you know any other tasks where we can use this approach?
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287. Find the Duplicate Number
A super task that demonstrates various approaches to marking elements to achieve specific goals.
I liked the 4th approach, but maybe just because I didn't fully realise the next one
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295. Find Median from Data Stream
That's an excellent task!
The approach with heaps shows us how we can be in the middle of the stream without heavy calculations.
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977. Squares of a Sorted Array
This small problem illustrates that if the list is sorted, we can use pointers.
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211. Design Add and Search Words Data Structure
This one with Trie also.
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648. Replace Words
It is a nice example of how a Trie helps with dictionary problems.
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208. Implement Trie (Prefix Tree)
- Set getters and setters
- If you are looking only for the part of the word, think about how you will separate it from the full word search.
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295. Find Median from Data Stream
It is an excellent problem with different approaches to solve.
- Multiset in C++ is always sorted
- You can keep your "pointer" in the middle of the set
- Read your task carefully
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1642. Furthest Building You Can Reach
It is an interesting problem with interesting solutions.
:) History can help.
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285. Inorder Successor in BST
When I write the code for Trees, it looks like a tree with (if/else/while blocks), when I see the editor's code, I am happy like I took some fruit from this tree.
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253. Meeting Rooms II
I finally broke the streak of unresolved tasks.
I hope my solutions weren't so bad.
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235. Lowest Common Ancestor of a Binary Search Tree
Finally, I have understood the difference between a Binary Search Tree and a Binary Tree.
This is a great problem for this.
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285. Inorder Successor in BST
This is a significant task that shows how elegant and simple the proper solution could be.
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