lcp

[lcp @lcpp119]

@PhysicsHateAcc You have k=6 positions and you can put one of the n=5 odd digits in each, so it's 5*5*5*5*5*5=5^6=n^k

[lcp @lcpp119]

@hyelilic 5/(3tanα)-4/3=-6/3
5/(3tanα)=-2/3
3tanα/5=-3/2
tanα=-5/2

[lcp @lcpp119]

@cloudnotez Hi, it's 5/(4-x²)≥0 so -2<x<2

[lcp @lcpp119]

@minnnstu___ If it's a²-b²=25 then 9a²-4a²=225, a²=45 and b²=20

[lcp @lcpp119]

@minnnstu___ Is it a-b=5 or a²-b²=5²?

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@minnnstu___ a-b=5, b=2/3a
3a-2a=15
a=15 b=10

[lcp @lcpp119]

@silverinth Hi, it's good, but the last part i would say l'italia sembra essere un paese incredibile che voglio davvero visitare per conoscere meglio la lingua, la storia e la cultura.

[lcp @lcpp119]

@lifesp0 Manicure is more profitable, so she needs to do one pedicure and the rest of the time manicures.
45+18×25=495$ is the max daily

[lcp @lcpp119]

@trishstudies The highest is where sin=1, so y=105+115=220;
for the distance of the peak 220=105sin(0.008x)+115, sin(0.008x)=1, 0.008x=π/2+πn, the first max is with n=0 so x=π/(2×0.008)

[lcp @lcpp119]

@jooniiwithlove It's the square diagonal - square side =side√2-side=side(√2-1)

[lcp @lcpp119]

@spookyfairies It worked for me

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@faymesstudytwtt g(x)=f(x+k)
8=(4+k)^3
2=4+k, k=-2
g(x)=(x-2)^3

[lcp @lcpp119]

@hinawotari Just integrals linearity property

[lcp @lcpp119]

@hinawotari 5∫(cos4t)dt-3∫(sin2t)dt=
(sin4t)5/4 - (-cos2t)3/2 +c=
(sin4t)5/4 + (cos2t)3/2 +c

[lcp @lcpp119]

@kaedeC25H28N6O7 U have to see how the last digit behaves with exponentiation and how often it repeats, then u divide the exponent by the number of repetitions and see the remainder of the division.
3^1=3, 3^2=9, 3^3=7, 3^4=1, 3^5=3,...; 4 repetitions: 2020/4=505 rem=0; the last digit is 1

[lcp @lcpp119]

@jaej__oong P=90-53=37°

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@parangMD Tactile stimuli

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@amandastudytwt Hi i can help u

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@medusascry z=ln[tg(xy)/y] and dz/dy=x/[tg(xy)cos^2(xy)]-1/y

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@studysparks Oven, dishwasher, washing machine