Manan Chhajed

swe 2 | ex-zomato, deutsche bank

[Manan Chhajed @manan_c288]

Career update:

Joined @zomato as a software engineer intern this week!

[Jarred Sumner @jarredsumner]

Rewriting Bun in Rust

https://t.co/Rl8bcaxBFc

[Manan Chhajed @manan_c288]

Testing

[Manan Chhajed @manan_c288]

@AmazonHelp @amazon

[Manan Chhajed @manan_c288]

@amazonIN
My Amazon account has been taken over. My order IDs are now linked to an unknown email. Support is not resolving. Need urgent help.

[Manan Chhajed @manan_c288]

@dhrxvtwts @zomato Messaged an employee for referral

[Manan Chhajed @manan_c288]

Career update:

Joined @zomato as a software engineer intern this week!

[Manan Chhajed @manan_c288]

@whynesspower @zomato Thanks bro!

[Manan Chhajed @manan_c288]

@BudhirajaMadhav @zomato Thanks!

[Manan Chhajed @manan_c288]

@HarshitGup55383 @zomato Messaged an employee for referral

[Manan Chhajed @manan_c288]

@Kartikey_Singh4 Congrats!

[Manan Chhajed @manan_c288]

@RAhulBALani21 @zomato Employee referral

[Manan Chhajed @manan_c288]

@selfxiron41001 @zomato offcampus

[Manan Chhajed @manan_c288]

@shivambhadani_ Congrats Shivam!

[Deedy @deedydas]

OpenAI o3 is 2727 on Codeforces which is equivalent to the #175 best human competitive coder on the planet.

This is an absolutely superhuman result for AI and technology at large.

[Manan Chhajed @manan_c288]

Gave a codechef contest after a long time
Secured global rank 91 in Div. 1, solved 4/6 problems

[Manan Chhajed @manan_c288]

World Rank 315 out of 36,000+ folks in today's LeetCode Biweekly Contest 138

[Manan Chhajed @manan_c288]

@Mmanav45 Sure

[Manan Chhajed @manan_c288]

Codeforces 968 (Div. 2)
5/8 problems solved, ranked 640 globally.
D2 was tough, 5 wrong answers, but got it right in the last 5 minutes 😎
Overall, a good contest

[Manan Chhajed @manan_c288]

@utsxvrai Yes, might help, extending the logic of D1 to D2

[Manan Chhajed @manan_c288]

@maunderer001 Practice🗿

[Manan Chhajed @manan_c288]

@HarshKumar99283 few edge cases, and some trick to calculate that quickly
You can check my submission, will be more clear

[Manan Chhajed @manan_c288]

@HarshKumar99283 if i is not one of mex1, you can use any one of edges mex1 --> mex2
and not use it again
so max over all far[edges from mex1 that are not mex2]

basically make a graph with edges mex1 --> mex2