@apaginaseria A × A × A = 3
A³ = 3
A = ³√3
B × B × B = 6
B³ = 6
B = ³√6
C × C × C
C³ = 9
C = ³√9
A × B × C = ³√(3 × 6 × 9)
A × B × C = ³√[(3) × (3 × 2) × (3 × 3)]
A × B × C = ³√(3³ × 2 × 3)
A × B × C =「3 × ³√6」
o certo seria ter uns + pra nao dar número quebrado, mas n tem