john rambo

Linux System Administrator
RHCA Certified
Interested in Linux, automation and infrastructure.
Sharing what I learn and build.
Open to freelance opportunitie

[john rambo @opsfortech]

@BholanathDutta

[john rambo @opsfortech]

@geniuscyp

[john rambo @opsfortech]

@IQTestBrain 85

[john rambo @opsfortech]

@Mishi_051 Does something this simple really need to be calculated?

[john rambo @opsfortech]

@terrywillett666 @IQTestBrain The calculation can only go this far; it is impossible to proceed further because it cannot be proven that these two angles have been bisected.

[john rambo @opsfortech]

@Quizmania0

[john rambo @opsfortech]

@BholanathDutta

[john rambo @opsfortech]

@dalceshere

[john rambo @opsfortech]

@Quizmania0

[john rambo @opsfortech]

@Surinder1531954 @Mishi_051 No, the original image does not indicate 90 degrees; if it were 90 degrees, there would be a clear marking.

[john rambo @opsfortech]

@waldrapas @Mishi_051 1 and 2 are equal.

[john rambo @opsfortech]

@IQTestBrain

[john rambo @opsfortech]

@BholanathDutta

[john rambo @opsfortech]

@Quizmania0

[john rambo @opsfortech]

@BholanathDutta Step 1: Calculate angle BEC
(180 - 80) / 2 = 50
Step 2: Calculate angle ADC
180 - 50 - 30 = 100
Step 3: Calculate x
180 - 100 = 80

[john rambo @opsfortech]

@jagustav59 @Mindsparkx__ As long as the approach is correct, that's fine; I didn't look at the scale of the diagram.

[john rambo @opsfortech]

@BholanathDutta

[john rambo @opsfortech]

@Ameela_56