Patrick Hulin

I delete my old tweets. Opinions and mistakes mine alone. he/him

[Patrick Hulin @phutrick]

Building a perfect clone of 1993 game SimTower: https://t.co/KQg7FH7Y07

[Patrick Hulin @phutrick]

@moyix I'm going to try this now

[Patrick Hulin @phutrick]

@moyix Very cool!!!

[Patrick Hulin @phutrick]

@mnolangray Don't forget Connecticut...

[Patrick Hulin @phutrick]

@sdamico @Kazanjy I don't know about SF in particular, but typically pre-medicare retirement (this is a huge expense for a cop that retires at 45), and then Medicare Advantage to add additional coverage on top of base Medicare for retirees.

[Patrick Hulin @phutrick]

@jc_gilbert @haider1 it's way cheaper though

[Patrick Hulin @phutrick]

@GwenDekker so cool!

[Patrick Hulin @phutrick]

@RSGAT @Katchin05 It’s not the penal statute, but you can’t convince me that our legalization law starting at 21a-420 is an accident. Even worse, it’s chapter 420h.

[Patrick Hulin @phutrick]

@Matt_Blumenthal @Jaryehperry @DFANewHaven I have never seen legal authority for the proposition that the General Assembly can't designate a brand name.

[Patrick Hulin @phutrick]

@MarketUrbanism CT has a good model that conditions all economic development funding on reporting of building permit to the state. See CGS 8-3l.

[Patrick Hulin @phutrick]

@GwenDekker @BinarySoloMTG I would simply win more than 60% of the time

[Patrick Hulin @phutrick]

@Urban_Dispatch @hartfordline You can definitely see it on the train. Fuller than it’s ever been

[Patrick Hulin @phutrick]

@GwenDekker I’m here!

[Patrick Hulin @phutrick]

@GwenDekker Me of course

[Patrick Hulin @phutrick]

@NTallapragada congratulations naren!!!

[Patrick Hulin @phutrick]

@ccanonne_ In particular, for any multiple of exp(x) epsilon, eventually |u’| goes below half epsilon exp(x), and I believe you can compute a point fairly easily at which |u| must be permanently below epsilon exp(x). Not as clean as some of the other solutions, of course.

[Patrick Hulin @phutrick]

@ccanonne_ Define u = e^x f, so f+f’ = exp(-x)u’. Then we’ve reduced the problem to proving that u’ is subexponential => u is subexponential. There may be a clever way to do it, but the obvious is to do some slightly complicated algebra with epsilons that I believe works.

[Patrick Hulin @phutrick]

@wang_seaver Feel free to reach out if you ever want to talk CT energy policy :)

[Patrick Hulin @phutrick]

@GwenDekker what are you thinking about it though