@_xpqzl solved!
WEN YOU LOOK INTO THE ABYSS...
...YOU ARE THE ABYSS!!! Send this token to the wallet you want to receive the treasure and wait for new instrunctions.
@CryptoCloaks LOL. Have you checked your email to see if you have any https://t.co/Lo4PlEueJK files sent to you by Blockstream? (Assuming this wallet is older than Jan 25th 2021?) If so, this could be a multisig wallet and knowing this will greatly help with bruteforcing it
Congratulations to the solver! Solution was to use paint, photoshop, or an online image steganography tool on the image. This will reveal wingdings characters hidden in the image as just off white pixels. The two symbols on the image in wingdings are 47, which a google of this and the word cipher will point you to using ROT47 cipher on the decoded wingdings. This gives the private key to the prize address π
mmmm the issue I was facing was I wanted to keep all the transaction in the original wallet. Didn't want it to become tainted by moving the full supply to my own wallet, then adding liquidity. At the same time as I was making the pool, someone posted a reply on twitter saying they had also solved the puzzle. This meant if I sent any SOL to the wallet, they could have taken the tokens and my SOL I sent. So only used the SOL that was in the wallet due to that risk. The distribution does seem to be improving somewhat, so hopefully that will continue
@snaxion 3 * 1 * 2 * 5 * 3 * 23 * 21 * 2 * 13 * 58 * 39 * 8
= 20,452,461,120
12! = 479,001,600
20,452,461,120 * 479,001,600
= 9.7967616e+18 which is still too many to brute.
Will need either partial order or more letters if it is out of order.