I'm coming, Risa! I can't express how I feel about being able to listen to Risa live. You know the feeling the first time I listened to her voice? It's about 16 years ago! Today, I still love her songs. See you in 7 June🤟
#LiSA#Risa#LiVEisSmileAlways
@SamuelGWalters 3. A* maps injectively on the eigenvectors of AA*, hence, A*A has k linearly independent eigenvectors with eigenvalue 1. For example, if u is a non zero eigenvector of AA*, then A*A(A*u) = A*u.
My Lab is recruiting a postdoc and Ph.D. students studying vegetation dynamics under climate change and human activities at @VanderbiltU. Includes remote sensing, #GEE, #urbantree, #fire, #lightpollution, and modeling. Please RT & thanks!
For details: https://t.co/BKRdaZmfuV
If i consider the more general case, abelian group of abelian homomorphism, it turns out that this abelian group consists of linear map over the underlying field. To write the proof, I need a careful analysis on the indices.
I am counting dimension of certain vector spaces. Based on previous results, it should be 17. But, actual counting give me 18. I wonder what happens to the extra 1 dimension 🤔
Should there be new structure come out?
@littmath@NilesTopologist @KamerynJW Using tikz, you can draw the shape as "smooth" as you want, using more steps to the curve. Normally, in my situation, 200 steps was enough to produce smooth curve.