@Sonic_Pi Hi! When I start up Sonic Pi, I get the welcome screen and then it disappears and turns into a blank page. I can't open Sonic Pi after that. Is there a way I can fix this?
@CollegeBoard After submitting my answers for my AP Physics 1 exam last Friday 6/26, I got a page that said "loading" for over an hour and never received a confirmation screen or email submission instructions. Is there a way I can check to make sure my answers went through?
@JacobsPhysics It's been over 30 mins since I submitted my AP answers, but I'm still seeing the spinning wheel with "loading" in the middle. What should I do now? I don't see a link for submitting by email, either.
@JacobsPhysics@MrJBphysics That's fine, I understand and thank you for offering to help with one part. Is the answer I got for part aii correct? I just want to make sure I did that short part right. Thank you again and good luck grading the rest of the exams!
@MrJBphysics@JacobsPhysics@bwilliams025 Thank you so much for the physics lessons and for answering our questions on Twitter. It's been a very helpful couple of weeks.
@JacobsPhysics Got it, so any work done by external forces on the book doesn't change its mechanical energy because they cancel out. Is that something I need to remember for the future for similar problems?
@bwilliams025@JacobsPhysics I understand that changing speed would definitely change K which would change the total mechanical energy, but I still don't understand how Earth doesn't change the total mechanical energy; doesn't it do work on the book even though it's not part of the system?
@JacobsPhysics I'm still confused about part (i) in question 1. Even though Earth isn't part of the system, wouldn't Earth doing work on the book system cause a change in mechanical energy? Isn't that the definition of work?
@JacobsPhysics@MrJBphysics Do we have to write a page number on our response if we're typing it? If not we just have to write our ID number and initials right?
@MrJBphysics In part e of the practice question, couldn't R and v also have an inverse relationship b/c if you divide both sides by v you get R/v, so as one increases the other decreases? (sorry that's a really dumb question)