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rebranding old games & calling them new... the 'new' versions cost more then the original but the only thing 'new' about them is their outrageous price tag..
@SDonutin@Halo its a 25 year old game that didnt cost that much when it was first released and the only thing new about it now...is the graphics but for the same price you can get the entire collection.. which is a far better deal, its a straight up no brainer..
@SkylinesUltra24@BudgetGoku@Halo have you? it didnt cost that much when it was originally released... 25 years ago, its the same game with updated graphics. theres nothing new about this..its a lazy cash grab.
@TheAshKnD@BudgetGoku@Halo when halo was first released, it didnt cost anywhere near 70$ so why...would i pay that now for the same game, i already own with slightly better graphics..buy the MCC and get more bang for your buck.
@TheAshKnD@BudgetGoku@Halo no, the really sad thing is the state of gaming & how many of the 'new' games, are just old ones with a new price tag...its a lazy way to price gouge ppl. pay the same price get MCC and win. paying almost 70 bucks for a game thats almost 25 years old is just stupid, imo.
@JustHappin@BudgetGoku@Halo you do understand that you can pay the same price and get the entire series... i bet you bought the new black flag too.. which is basically the same game as the original
The Sentinel Experimental Playlist begins at 1PM PT today! Find it then under Quickplay to queue it.
If you still need an ADS fix, you can queue it until the Sentinel Playlist goes live.
@Xach_the_Rat Tips are earned...want a good tip? do a good job, not going to tip someone doing the bare minimum simply because they expect it. You chose this profession knowing the situation.
@Rivilant i think you mean empulse lol.. i love how ppl are complaining about ADS when it was just added and has its own seperate 'experimental playlist'
@MZen012@renabaddie_ Edit; once 3 is out of the way the others can freely move in pairs. 1,2 then 4.5 and finally 6,7.
- i made a small error in my original reply when i mentioned 3 twice.
@MZen012@renabaddie_ the answer is 3, helps to read the entire problem. once 3 is out of the way the others can freely move, 1 and 2 then 3 and 4 then 5 and 6