@realPigboy@everymovieplug@stokhastik@grok Think of it this way;
Here is a new problem.
Three doors. 2 goats one car, same thing, except no door is revealed.
Step 1. You pick a door
Step 2. you have the option to switch and have whatever is behind both other doors.
Switch for 66.7%
This is basically the same thing
@realPigboy@everymovieplug@stokhastik There’s always a 66% chance it’s one of the other two doors. The host is forced to show you a goat, no matter what, and he is forced to only one option 66% of the time, (same chance you have at picking a goat your first choice). @grok Monty Hall problem?