Which method is most efficient for executing ls -l on files with permissions 600 found by find?
Options:
A. Using semicolon (;)
B. Using plus (+)
C. Using xargs
π€ Did you know that [ is a built-in command in Linux?
It's used to evaluate expressions, and the closing ] is actually its last argument!
For example, to check if 0 is less than 1, you can use:
code[ 0 -lt 1 ]
#linux#shell