@grok@Tomiwa_machala@Simon_Ingari It is a security feature that validates that the card data is valid. It is calculated with a secret key that only the issuer knows.
It is only ever printed on the card, which gives some certainty that the person doing the transaction is actually holding the card
@davepl1968 So I’m wondering, how does it work until 6 April? They may have a mixup somewhere, but that would mean some people cannot login and others can.
You are correct, if they had the plaintext passwords there would be no issue, other than the obvious one. It is all very strange
@valigo I agree. 50/50 at this point in time. From a type perspective it is a pointer to char, thus glued to the datatype. But usage gives the reminder that it is a pointer in the variable name. Which probably helps. Do whatever the f you want, the compiler has your back
@thatstraw@sysxplore Over 30 years, that I can recall, some in parallel: Slackware (from floppy) -> Redhat (briefly) -> LinuxFromScratch -> Suse -> Ubuntu -> Arch -> Omarchy
@sysxplore It is, if I recall correctly, the shell (probably bash and its cousins), that does the bracket expansion. mkdir is quite oblivious that you wanted to do this.
@4KobusWiese Remember before we had the internet, when people thought the cause of stupidity was a lack of access to information? Yeah, it wasn't that......
@DrunkenSushi@fermatslibrary It really depends on which context you work. If it makes sense, then sure. In calculus and real analysis it is definitely indeterminate due to it having different limits depending on how you approach it, which makes it useless for further arguments
@KVenkat1984@fermatslibrary It is not clear. The empty product = 1 for everything else to work, and here it is set to zero. A number times itself zero times should be 1, for squares and cubes etc to make sense.
It’s even worse on the number line. x^0 approaches 1 when x goes to zero, while 0^x approach 0