Almost Sure

George Lowther, Author of Almost Sure blog, on maths, probability and stochastic calculus.
Also on YouTube

[Almost Sure @Almost_Sure]

new YouTube video posted!

Are prime numbers random?

(link below)

[Almost Sure @Almost_Sure]

@mouse_math I’m guess it’s because you can’t take the union of a sequence of iterated power sets in Z. So you don’t have as big sets, and can build a model inside ZF

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@mouse_math Interesting

[Giulio Tiozzo @tiozzo_giulio]

Solution: release the Yang Mills paper to mathematicians, and keep it secret from physicists

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@JasonRute Didn’t even know that was an open question!

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Morning. What major conjectures are we expecting to be resolved today?

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@numberphile https://t.co/kzcjd4gz1G

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“They don’t know I’m universal for chaotic maps”

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@miniapeur If π is a projection representing an observation and k any observable, then the second one is the correct way to restrict to π being observed.
The first way assumes commutativity

Pikachu is correct to prefer the second!

[Almost Sure @Almost_Sure]

@PantsToTravel glad to see it was just your feet, thought scooter muffler was some kind of euphemism at first

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@UnderdoneElm69 @Riazi_Cafe_en No you don’t need to use Legendre in the final proof, but what it does do, is guarantee that there is such a proof

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@miniapeur watched a moocake video about it recently

“Why you should despise gambling ads”

https://t.co/yPKnSgzZnk

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@Riazi_Cafe_en in this case there’s no solutions mod 32 (unless all even).

as n is even replace by 2n

10n²=18a²+9b²+3c²

b,c can’t both be odd as that gives 2n²=2a²+4 (mod 8). So both even. Replace by 2b,2c

5n²=9a²+18b²+6c²

n,a can’t both be odd otherwise 4= 2(b²-c²) (mod 8)

so a even. QED

[Almost Sure @Almost_Sure]

@Riazi_Cafe_en It’s a quadratic form so, by Legendre’s theorem it has a nonzero integer solution iff it has one in R and one modulo each prime power pⁿ (and not a multiple of p). So these problems can always be resolved by modulo arithmetic

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@tszzl

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@subcountability unsure exactly but it seems like we don’t take as many drugs as Americans would like

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We rarely get headaches. Don’t have the disposable income.

They’re a luxury item over here

[Audra Worlow 🇺🇸 @audrawrongspeak]

This European ibuprofen discourse surely isn’t real.

I get regular pressure headaches due to the weather (when it rains the barometric pressure changes cause me headaches)

You guys just…don’t take anything?

You just stop working every time you have a headache?

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@schweingehtbree @DiracDeltaFunk So R-{0} is closed under finite products

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@tszzl

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@WrathofMathEDU as that was also a leap year, was 2016 the longest year on record?