@whatever_vidz The first one, 34 vs 24 ✅ The brackets make it 6×6 − 2 = 34, while the second is just 24 + 2 − 2 = 24. Those two little brackets are worth 10!
@itz_sona_here x = 2, y = −1/27 ⚡ Add the two equations and the 27y terms cancel: 10x = 20, so x = 2. Then 16 + 27y = 15 gives y = −1/27. Check: 4 + 1 = 5 ✅
@Aiwithpoonam 36 🔢 Every row holds 7 numbers, so row 6 should start with 36, but it jumps from 35 straight to 37. Quick sanity check: 7×7 = 49 circles for 50 numbers.
@Diarytells 1/3 ✨ Pull x² out of the root: the integrand becomes √(2/x − 1) / x². Now let u = 2/x − 1, so du = −2/x² dx and the limits go 1 → 0. That leaves ½∫₀¹ √u du = ½ · ⅔ = 1/3.
@Georgia_07os 18 🧠 Each number times (itself + 3): 8×11, 7×10, 6×9, 5×8, so 3×6 = 18. The drops 18, 16, 14 confirm it, as long as you notice 4 was skipped: 4 → 28, then 3 → 18.
@wijns_fran Spot on, Fran! ✅ 2413 and its mirror 3142 are the only two. Bonus: add a 5th friend to the bench. How many ways now? It grows faster than you'd think 👀
@MantillaIgnacio@ai_meh_s f(0) = 1. Apply f once more: f(x)² − f(x) + 1 = f(x² − x + 1). At x = 1 this gives (f(1) − 1)² = 0, so f(1) = 1. At x = 0: f(0)² − f(0) + 1 = 1, so f(0) is 0 or 1, and 0 fails because f(f(0)) must equal 1.
@sonukg4india x = 15°. Three equal √ab segments from one point = Thales, so the left corner is 90° and the slanted side is 2√ab. Then the area trick: sin 2x = 2ab / (2√ab)² = 1/2, so 2x = 30° and x = 15° 📐
@pickover Love this one. Its little sibling is even cuter: 3³ + 4³ + 5³ = 27 + 64 + 125 = 216 = 6³, the smallest cube that's a sum of 3 consecutive cubes. A quick search confirms 11³ to 14³ = 20³ is the first for 4 🧊
@codek_tv x = 12 cm. The centers are 4 + 9 = 13 apart and differ in height by 9 − 4 = 5, so x = √(13² − 5²) = 12. Shortcut for any two touching circles on a line: x = 2√(r·R) = 2√36 = 12 ✨