felt inspired by this and disproved wowii conjecture 194 with my close friend codex
take K₁₁ ∨ K̄₄ and hang a leaf off 3 of the 4 new vertices:
∑ᵥ α(G[N(v)]) = 54
α(G) = 4 = 1 + 54/18
but 3 leaves can't be the 2 ends of a hamiltonian path. lean checked :)
hello there the jacobian conjecture is false thanx to my close friend akhil for asking about it and my other close friend fable for working during the world cup final
((1+xy)^3 z + y^2 (1+xy) (4+3xy), y + 3 x (1+xy)^2 z + 3 x y^2 (4+3xy), 2 x - 3 x^2 y - x^3 z): \C^3\to \C^3, has jacobian determinant -2, and sends (0, 0, -1/4), (1, -3/2, 13/2), and (-1, 3/2, 13/2) to (-1/4, 0, 0)
felt inspired by this and disproved wowii conjecture 194 with my close friend codex
take K₁₁ ∨ K̄₄ and hang a leaf off 3 of the 4 new vertices:
∑ᵥ α(G[N(v)]) = 54
α(G) = 4 = 1 + 54/18
but 3 leaves can't be the 2 ends of a hamiltonian path. lean checked :)
felt inspired by this and disproved wowii conjecture 194 with my close friend codex
take K₁₁ ∨ K̄₄ and hang a leaf off 3 of the 4 new vertices:
∑ᵥ α(G[N(v)]) = 54
α(G) = 4 = 1 + 54/18
but 3 leaves can't be the 2 ends of a hamiltonian path. lean checked :)
felt inspired by this and disproved wowii conjecture 194 with my close friend codex
take K₁₁ ∨ K̄₄ and hang a leaf off 3 of the 4 new vertices:
∑ᵥ α(G[N(v)]) = 54
α(G) = 4 = 1 + 54/18
but 3 leaves can't be the 2 ends of a hamiltonian path. lean checked :)
felt inspired by this and disproved wowii conjecture 194 with my close friend codex
take K₁₁ ∨ K̄₄ and hang a leaf off 3 of the 4 new vertices:
∑ᵥ α(G[N(v)]) = 54
α(G) = 4 = 1 + 54/18
but 3 leaves can't be the 2 ends of a hamiltonian path. lean checked :)
felt inspired by this and disproved wowii conjecture 194 with my close friend codex
take K₁₁ ∨ K̄₄ and hang a leaf off 3 of the 4 new vertices:
∑ᵥ α(G[N(v)]) = 54
α(G) = 4 = 1 + 54/18
but 3 leaves can't be the 2 ends of a hamiltonian path. lean checked :)
felt inspired by this and disproved wowii conjecture 194 with my close friend codex
take K₁₁ ∨ K̄₄ and hang a leaf off 3 of the 4 new vertices:
∑ᵥ α(G[N(v)]) = 54
α(G) = 4 = 1 + 54/18
but 3 leaves can't be the 2 ends of a hamiltonian path. lean checked :)
felt inspired by this and disproved wowii conjecture 194 with my close friend codex
take K₁₁ ∨ K̄₄ and hang a leaf off 3 of the 4 new vertices:
∑ᵥ α(G[N(v)]) = 54
α(G) = 4 = 1 + 54/18
but 3 leaves can't be the 2 ends of a hamiltonian path. lean checked :)
felt inspired by this and disproved wowii conjecture 194 with my close friend codex
take K₁₁ ∨ K̄₄ and hang a leaf off 3 of the 4 new vertices:
∑ᵥ α(G[N(v)]) = 54
α(G) = 4 = 1 + 54/18
but 3 leaves can't be the 2 ends of a hamiltonian path. lean checked :)
felt inspired by this and disproved wowii conjecture 194 with my close friend codex
take K₁₁ ∨ K̄₄ and hang a leaf off 3 of the 4 new vertices:
∑ᵥ α(G[N(v)]) = 54
α(G) = 4 = 1 + 54/18
but 3 leaves can't be the 2 ends of a hamiltonian path. lean checked :)
felt inspired by this and disproved wowii conjecture 194 with my close friend codex
take K₁₁ ∨ K̄₄ and hang a leaf off 3 of the 4 new vertices:
∑ᵥ α(G[N(v)]) = 54
α(G) = 4 = 1 + 54/18
but 3 leaves can't be the 2 ends of a hamiltonian path. lean checked :)